What will be the molality of the solution containing $18.25 g$ of $H C l$ gas in $500 g$ of water?

0.1 m

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1 m

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0.5 m

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1 m

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Solution

The correct option is C $1 m$
Molality $(m) = \frac{N o . o f m o l e s o f s o l u t e}{M a s s o f s o l v e n t (i n k g)}$

Molality $= \frac{W_{B} \times 1000}{M_{B} \times W_{A} (i n g)} = \frac{18.25 \times 1000}{36.5 \times 500}$

$(∵$ molar mass of $H C l = 36.5 g m o l^{- 1})$
$= 1 m$

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