What will be the order of $1^{s t}$ ionisation energy

L i > N a > K

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K > L i > N a

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N a > L i > K

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L i > K > N a

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Solution

The correct option is A $L i > N a > K$
Down the group ionisation decreases due to increase in the size of an atom.

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Similar questions

The order of decreasing ionisation enthalpy in alkali metals is
(a) Na> Li > K> Rb (b) Rb< Na< K< Li
(c) Li > Na> K> Rb (d) K< Li < Na < Rb

Arrange the following as per instructions given in the brackets.

(a) Mg. Cl, Na, S, Si (decreasing order of atomic size)

(b) Cs, Na, Li, K, Rb (increasing metallic character)

(d) Cl, F, Br, I (increasing electron affinity)

(e) Cs, Na, Li, K, Rb (decreasing electronegativity)

What will be the order of $I^{s t}$ ionisation energy

N a, L i, R b,

K

(L i^{\oplus}, N a^{\oplus}, K^{\oplus}, R b^{\oplus})

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