What will be the pressure of 0.1 mole $S O_{3}$ gas filled in a 2 litre container at 300 K temperature?

2.46 bar

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1.23 bar

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0.01 bar

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0.22 bar

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Solution

The correct option is B 1.23 bar
By using ideal gas equation:
PV = nRT
P = ?
V = 2 L
n = 0.1 mol
R = $0.0821 L a t m K^{- 1} m o l^{- 1}$
T = 300 K
substituting the value in the above equation
$P \times 2 = 0.1 \times 0.0821 \times 300 P = \frac{0.1 \times 0.0821 \times 300}{2} P = 0.1 \times 0.0821 \times 150 P = 1.23 b a r$ .

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What will be the pressure of 0.1 mole SO3 gas filled in a 2 litre container at 300 K temperature?

The correct option is B 1.23 barBy using ideal gas equation: PV = nRT P = ? V = 2 L n = 0.1 mol R =0.0821 L atm K−1 mol−1 T = 300 K substituting the value in the above equation P×2=0.1×0.0821×300P=0.1×0.0821×3002P=0.1×0.0821×150P=1.23 bar.

What will be the pressure of 0.1 mole $S O_{3}$ gas filled in a 2 litre container at 300 K temperature?