Question

What will be the value of ${\Delta G}^0$, If equilibrium constant for a reaction is $10$?

Answer 1

$△G^{\circ }=-2.303RT\log K$

$K=10$

$△G^{\circ }=-2.303RT{\log }_{10}^{10}$

$=-2.303RT$ $log1$ $[\because \log 1=0]$

$=0$