What will be the value of remainder when 111111111 - 64 terms -22222222 - - -55 terms is divided by 18 -

The correct option is C 2[(111111111 …… 64 terms) × (22222222 …… 55 terms)]/18 =2 × Remainder of [(111111111 …… 64 terms) × (111111111 …… 55 terms)]/9→ Rema ...

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Quantitative Aptitude

Divisibility Rule for Composite Numbers

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Question

What will be the value of remainder when (111111111 ..... 64 terms) $\times$ (22222222 ........ 55 terms) is divided by 18?

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Solution

The correct option is B 2
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (22222222 \dots \dots 55 t e r m s)]}{18}$
$= 2 \times$ Remainder of
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (111111111 \dots \dots 55 t e r m s)]}{9} \to R e m a i n d e r = 2 \times 1$ = 2

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What will be the value of remainder when (111111111 ..... 64 terms) × (22222222 ........ 55 terms) is divided by 18?

The correct option is B 2[(111111111……64 terms)×(22222222……55 terms)]18 =2× Remainder of [(111111111……64 terms)×(111111111……55 terms)]9→Remainder=2× 1 = 2

What will be the value of remainder when (111111111 ..... 64 terms) $\times$ (22222222 ........ 55 terms) is divided by 18?

The correct option is B 2
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (22222222 \dots \dots 55 t e r m s)]}{18}$
$= 2 \times$ Remainder of
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (111111111 \dots \dots 55 t e r m s)]}{9} \to R e m a i n d e r = 2 \times 1$ = 2