What will be the value of remainder when 111111111 - 64 terms -22222222 - - -55 terms is divided by 18 -

The correct option is C 2[(111111111 …… 64 terms) × (22222222 …… 55 terms)]/18 =2 × Remainder of [(111111111 …… 64 terms) × (111111111 …… 55 terms)]/9→ Rema ...

Byju's Answer

Other

Quantitative Aptitude

Divisibility Rule for Composite Numbers

What will be ...

Question

What will be the value of remainder when (111111111 ..... 64 terms) $\times$ (22222222 ........ 55 terms) is divided by 18?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (22222222 \dots \dots 55 t e r m s)]}{18}$
$= 2 \times$ Remainder of
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (111111111 \dots \dots 55 t e r m s)]}{9} \to R e m a i n d e r = 2 \times 1$ = 2

Suggest Corrections

Similar questions

Q. What will be the remainder when

(19)^{23}

is divide by

18

Q. What is the remainder when

7 + 77 + 777 + 7777 + \dots

(till 100 terms) is divided by 8?

Q. When

9^{t h}

term of an A.P. is divided by its

2^{n d}

term the quotient is 5 & when

13^{t h}

term is divided by the

6^{t h}

term, the quotient is 2 and remainder is 5. The sum of first term and the common difference of the A.P. will be equal to .......... ?

Q. Polynomial

P (x)

contains only terms of odd degree. When

P (x)

is divided by

(x - 3)

, the remainder is

6

. If

P (x)

is divided by

(x^{2} - 9)

, then the remainder is

g (x)

. Then the value of

g (2)

Q. A polynomial

P (x)

contains only terms of even degree, when

P (x)

is divided by

(x + 1)

, the remainder is

- 2

. If

P (x)

is divided by

(x^{2} - 1)

then find the remainder.

What will be the value of remainder when (111111111 ..... 64 terms) × (22222222 ........ 55 terms) is divided by 18?

The correct option is C 2[(111111111……64 terms)×(22222222……55 terms)]18 =2× Remainder of [(111111111……64 terms)×(111111111……55 terms)]9→Remainder=2× 1 = 2

What will be the value of remainder when (111111111 ..... 64 terms) $\times$ (22222222 ........ 55 terms) is divided by 18?

The correct option is C 2
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (22222222 \dots \dots 55 t e r m s)]}{18}$
$= 2 \times$ Remainder of
$\frac{[(111111111 \dots \dots 64 t e r m s) \times (111111111 \dots \dots 55 t e r m s)]}{9} \to R e m a i n d e r = 2 \times 1$ = 2