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Question

What will be the volume of gas at STP which is liberated at anode on electrolysis of $$CuSO_4$$ solution by a current of $$5$$ ampere for $$2$$ minutes?


A
0.0995 L
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B
0.0672 L
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C
0.0174 L
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D
0.0348 L
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Solution

The correct option is C $$0.0672$$ L
$$i= 5 \ amp$$
$$t= 2 \ min =2 \times 60 \ sec$$
$$Cu^{2+} \ n=2$$
$$Atomic \ Mass = 63.5 \ g$$
$$m= \cfrac {Atomic \ Mass}{n \times F} \times i \times t$$
$$\cfrac {m}{Atomic \ Mass}= \cfrac {i \times t}{n \times F}$$
$$Moles = \cfrac {i \times t}{n \times F}$$
$$Moles = \cfrac {5 \times 2 \times 60}{2 \times 96500}=0.003$$
$$1$$ mole at STP $$\rightarrow 22.4 \ L$$
$$0.003$$ mole at STP $$\rightarrow 22.4 \times 0.003 = 0.0672 \ L$$

Chemistry

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