Question

# What would be the radius of second orbit of $${He}^{+}$$ ion?

A
1.058˚A
B
3.023˚A
C
2.068˚A
D
4.458˚A

Solution

## The correct option is A $$1.058\mathring { A }$$Radius of the nth orbit, $$r_n = 0.529 \dfrac{n^2}{Z}$$   $$A^o$$For $$He^+$$ ion, $$Z = 2$$Radius of 2nd orbit, $$r_2 = 0.529\dfrac{2^2}{2}$$$$\implies r_2 = 1.058$$ $$\mathring A$$Physics

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