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Question

What would be the radius of second orbit of $${He}^{+}$$ ion?


A
1.058˚A
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B
3.023˚A
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C
2.068˚A
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D
4.458˚A
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Solution

The correct option is A $$1.058\mathring { A } $$
Radius of the nth orbit, $$r_n = 0.529  \dfrac{n^2}{Z}$$   $$A^o$$
For $$He^+$$ ion, $$Z = 2$$
Radius of 2nd orbit, $$r_2 = 0.529\dfrac{2^2}{2}$$
$$\implies   r_2  =  1.058$$ $$\mathring A$$

Physics

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