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Question

When 0.44 g of a colourless oxide of nitrogen occupies 224 mL at 1520 mm of Hg and 546 K , then the oxide is


  1. N2O5

  2. N2O3

  3. NO2

  4. N2O


Solution

The correct option is D

N2O


Volume of oxide is calculated at STP conditions by the formula P1V1T1=P2V2T2

1520 × 224546 = 760 × V2273

V2 = 1520 × 224 × 273546 × 760  =224ml

Weight of the 22400ml oxide at STP = molecular weight

Weight of the 224ml = 0.44 g

Weight of the 22400ml = 44g

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