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Question

# When 1 gm of water changes from liquid to vapour phase at constant pressure of 1 atmosphere, the volume increases from 1cc to 1671cc. The heat of vaporisation at this pressure is 540 cal/gm. Increase in internal energy of water is(1 atmosphere=1.01×106dyne/cm2).

A
4200 J
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B
8200 J
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C
1200 J
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D
2100 J
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Solution

## The correct option is D 2100 JChange in Internal energy = Q in - work done It s a constant pressure work ∴wD=P(V2−V1) =1.01×105[1.671−1]×10−6=169.21s P=1atm =1.0.1×105Pa=1.01×106dynecm2Latent heat of vaporization =540calgm×(1gm)=540cal1cal=4.184J.=540×4.184=2259.36J∴ΔU=2259.36−169.21=2090Joules≈2100Joules

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