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Question

When 2 g of gas A is introduced into an evacuated flask kept at 25oC, the pressure was found to be 1 atm. If 3 g of another gas B is then added to the same flask containing A, the pressure becomes 1.5 atm. Assuming ideal behaviour, the ratio of molecular weights (MA:MB) is :

A
1:3
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B
3:1
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C
2:3
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D
3:2
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Solution

The correct option is A 1:3
MolesPressure
For A, 2MwA1 atm ......(i)

Pressure of B=1.51=0.5 atm
For B, 3MwB0.5 atm ......(ii)
Dividing (ii) by (i), we get,

3MwB×MwA2=0.51
MwAMwB=0.5×23=13
MwA:MwB=1:3

Therefore, the option is A

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