When $(3 - 2 i)$ is subtracted from $(4 + 7 i)$ , then the result is

1 + 5 i

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1 + 9 i

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7 + 5 i

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7 + 9 i

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Solution

The correct option is B $1 + 9 i$
We need to subtract $(3 - 2 i)$ from $(4 + 7 i)$
$∴ 4 + 7 i - (3 - 2 i)$
$= 4 + 7 i - 3 + 2 i$
$= 1 + 9 i$

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Similar questions

z = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 + 2 i & - 5 i 1 - 2 i & - 3 & 5 + 3 i 5 i & 5 - 3 i & 7 \end{matrix} ∣ ∣ ∣ ∣

If Z= $\frac{(13 - 5 i)}{(4 - 9 i)}$ find $z^{6}$

z = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 + 2 i & - 5 i 1 - 2 i & - 3 & 5 + 3 i 5 i & 5 - 3 i & 7 \end{matrix} ∣ ∣ ∣ ∣

z = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 + 2 i & - 5 i 1 - 2 i & - 3 & 5 + 3 i 5 i & 5 - 3 i & 7 \end{matrix} ∣ ∣ ∣ ∣

i = (\sqrt{- 1})

40 + 9 i > 12 + 5 i

\sqrt{- 1} = i

40 > 12

9 > 5

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