You visited us 1 times! Enjoying our articles? Unlock Full Access!

Remainder Theorem

When 3x3 + ...

Question

When $3 x^{3} + 2 x^{2} + 2 x + k$ is divided by $x + 2$ , the remainder is $4$ . Calculate the value of $k$ .

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

34

No worries! We‘ve got your back. Try BYJU‘S free classes today!

54

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $24$
Given the equation $3 x^{3} + 2 x^{2} + 2 x + k$ is divided by $x + 2$ the reminder is $4$ .
Put the value $x = - 2$ in equation, we get
$3 (- 2)^{3} + 2 (- 2)^{2} + 2 (- 2) k = 4$
$\Rightarrow 3 (- 8) + 2 (4) + 2 (- 2) + k = 4$
$\Rightarrow - 24 + 8 - 4 + k = 4$
$\Rightarrow k = 4 + 24 - 8 + 4$
$\Rightarrow k = 24$

Suggest Corrections

Similar questions

3 x^{3} + 2 x^{2} - x + 4

3 + 2 x

\frac{- 1}{8}

The remainder when $3 x^{3} + 2 x^{2} - x + 4$ is divided by $3 + 2 x$ is $\frac{- 1}{8}$ .

4

x^{3} + 2 x^{2} - x - k

x - 2

k

When $3 x^{3} + 2 x^{2} - x + 4$ is divided by $3 + 2 x$ the remainder is $\frac{- 1}{8}$ .

2 x^{3} + 3 x^{2} - 4 x + k

x + 2

3

k

Join BYJU'S Learning Program