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Question

When 8.4g of NaHCO3 is added to a solution of CH3COOH weight 20g.It is observed that 4.4g of CO2 is released into atmosphere and a residue is left behind.Calculate the mass of residue by applying law of conservation of mass

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Solution

The mass of residue, is CH3COONa solution, should be 24g of CH3COONa solution.
In this reaction, sodium bicarbonate reacts with acetic acid to produce sodium acetate, carbon dioxide and water
NaHCO3+CH3COOHCH3COONa+CO2+H2O
According to law of conversation of masses,
total masses of reactants = total masses of products
reactants are 8.4g NaHCO3 and 20g CH3COOH.
total mass of reactants is =28.4g
mass of residue = (28.4g reactants mass) (4.4g CO2)
= 24.0g residue (sodium acetate solution)
mass of residue is thus 24 grams.

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