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Question

When a ball is thrown vertically upwards, it goes through a distance of 19.6 m. find the initial velocity of the ball and the time taken by it to rise to the highest point. (Acceleration due to gravity, g = 9.8 m/s2​)

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Solution

Distance travelled by the ball = 19.6 m

Acceleration due to gravity = ​g = 9.8 m/s2

Let the initial velocity of the body = u

Final velocity of the ball = 0 m/s

Time taken by the ball to reach to the highest point = t

Using the third equation of motion, v2=u2-2gs

0=u2-2g×19.6u2=2×9.8×19.6=(19.6)2u=19.6 m/s

Now, using the first equation of motion for the ball thrown upward, v = u - gt

0 =u -gtt=ug=19.6 m/s9.8 m/s2=2 st=2 s


Time taken by the ball to reach the highest point = 2 s

And the initial velocity of the ball, u = 19.6 m/s

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