Question

# When a body is thrown with a velocity $$u$$ making an angle $$\theta$$ with the horizontal plane, the maximum distance covered, by it in horizontal direction is:

A
u2sinθg
B
u2sin2θ2g
C
u2sin2θg
D
u2cos2θg

Solution

## The correct option is C $$\dfrac {{u}^{2}\sin {2\theta}}{g}$$in horizontal directionvelocity is constant as there is no acceleration$$v=ucos\theta$$time of flight=$$\dfrac{2usin\theta}{g}$$range=maximum distance traveled in horizontal direction=vt=$$\dfrac{u^2sin2\theta}{g}$$Physics

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