Question

When a body lighter than water is completely submerged in water, the buoyant force acting on it is found to be n times its weight. The specific gravity of the material of the body is:

• A. $\frac{1}{1+n}$
• B. $\frac{1}{n}$
• C. $n$
• D. $n+\frac{1}{n}$

Answer 1

Answer: (B)

$\frac{1}{n}$

n(weight of body) $=$ Buoyant force acting
$\Rightarrow n\left(V{\rho }_{s}g\right)=n\left(V\rho g\right)$
$\frac{{\rho }_s}{\rho }=\frac{1}{n}$.