When a body moving with a speed of 20 m/s. stops in 20 seconds, what is the acceleration?

-1 m/s²

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 m/s²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-2 m/s²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 m/s²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
-1 m/s²

Given

u=20m/s , v=0m/s , t=20s

Using, v = u + at

0 = 20 + (a × 20)

a = -1 $m / s^{2}$

Suggest Corrections

Similar questions

Q. A body is moving in a circle with a speed of

1 m/s

. This speed increases at a constant rate of

2 m/s

every second. Assume that the radius of the circle described is

25 m

. The total acceleration of the body after

2 s

A van starts from rest, accelerates uniformly and attains a speed of $20 m / s$ in $25$ seconds. What is the acceleration of the van?

Q. A body starts from rest and travels

s m

2^{n d}

second, then, acceleration is

Q. Magnitude of acceleration of the two blocks is :
(Radius of pulley is

1 m

)

Figure depicts the motion of a particle moving along an x axis with a constant acceleration. The figure's vertical scaling is set by $x_{s}$ = 6.0 m. What is the particle's acceleration?

Join BYJU'S Learning Program

When a body moving with a speed of 20 m/s. stops in 20 seconds, what is the acceleration?

The correct option is A -1 m/s2 Given u=20m/s , v=0m/s , t=20s Using, v = u + at 0 = 20 + (a × 20) a = -1 m/s2

The correct option is A
-1 m/s²

Given

u=20m/s , v=0m/s , t=20s

Using, v = u + at

0 = 20 + (a × 20)

a = -1 $m / s^{2}$