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Question

When a convex mirror of focal 'f' produces an image (1/n)th of the size of the object, then distance of the object from the mirror is what


Solution

  magnification= focal length/focal length -object distance

m= f /(f -
 u)           (1).

HERE, 

m = +(1/n)  ; f = +f ; u= – u . (since mirror is convex).

So, using those, equation (1) becomes,

(1/n) = f /(f+u)    

or, (f+u)=nf

or, u = nf – f

or, u =(n – 1) f.
 

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