Question

# When a convex mirror of focal 'f' produces an image (1/n)th of the size of the object, then distance of the object from the mirror is what

Solution

## magnification= focal length/focal length -object distance m= f /(f - u)           (1). HERE,  m = +(1/n)  ; f = +f ; u= – u . (since mirror is convex). So, using those, equation (1) becomes, (1/n) = f /(f+u)     or, (f+u)=nf or, u = nf – f or, u =(n – 1) f.

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