When a current of $20 m A$ flows through a TG, the deflection of the needle is $30^{o}$ . If the current is increased to $40 m A$ , the deflection of the needle is

29^{o}

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39^{o}

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49^{o}

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59^{o}

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Solution

The correct option is C $49^{o}$
$B_{4} tan θ = \frac{μ_{0} i}{2 r}$
$\frac{i_{1}}{i_{2}} = \frac{tan θ_{1}}{tan θ_{2}}$
$\frac{tan 30^{o}}{tan θ_{2}} = \frac{20}{40}$
$tan θ_{2} = \frac{2}{\sqrt{3}}$
$= 49^{o}$

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When a current of 20mA flows through a TG, the deflection of the needle is 30o . If the current is increased to 40mA, the deflection of the needle is

The correct option is C 49oB4tanθ=μ0i2ri1i2=tanθ1tanθ2tan30otanθ2=2040tanθ2=2√3=49o

When a current of $20 m A$ flows through a TG, the deflection of the needle is $30^{o}$ . If the current is increased to $40 m A$ , the deflection of the needle is

The correct option is C $49^{o}$
$B_{4} tan θ = \frac{μ_{0} i}{2 r}$
$\frac{i_{1}}{i_{2}} = \frac{tan θ_{1}}{tan θ_{2}}$
$\frac{tan 30^{o}}{tan θ_{2}} = \frac{20}{40}$
$tan θ_{2} = \frac{2}{\sqrt{3}}$
$= 49^{o}$