Question

When a current of $4A$ between two coils changes to $12A$ in $0.5s$ in primary and induces an emf of $50mV$ in the secondary. Calculate the mutual inductance between the two coils.

Answer 1

$M=\frac{e_2}{d{i}_2/dt}=\frac{(50\times {10}^{-3})}{\left(8/0.5\right)}$

$=3.125\times {10}^{-3}H=3.125mH$