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Standard IX

Physics

Density

When a golf b...

Question

When a golf ball is lowered into a measuring cylinder containing water,the water level rises by 30 $c m^{3}$ when the ball is completely submerged. If the mass of ball in air is 33 g, what would be its density?

1.1 g / c m^{3}

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2.2 g / c m^{3}

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3.3 g / c m^{3}

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4.4 g / c m^{3}

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Solution

The correct option is A $1.1 g / c m^{3}$
Given, change in volume of water when the ball is submerged = $30 c m^{3}$
Now, the volume of water displaced = volume of ball when fully immersed
Hence volume of ball = $30 c m^{3}$
Mass = 33 g
So $D e n s i t y = \frac{m a s s}{v o l u m e} = \frac{33}{30} g c m^{- 3}$

$= 1.1 g c m^{- 3}$

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When a golf ball is lowered into a measuring cylinder containing water,the water level rises by 30 cm3 when the ball is completely submerged. If the mass of ball in air is 33 g, what would be its density?

The correct option is A 1.1 g/cm3Given, change in volume of water when the ball is submerged = 30 cm3 Now, the volume of water displaced = volume of ball when fully immersed Hence volume of ball = 30 cm3 Mass = 33 g So Density=massvolume=3330 g cm−3 =1.1 g cm−3

When a golf ball is lowered into a measuring cylinder containing water,the water level rises by 30 $c m^{3}$ when the ball is completely submerged. If the mass of ball in air is 33 g, what would be its density?