When a lead storage battery is discharged, then:

_{2}

is evolved

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lead is formed

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lead sulphate is consumed

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sulphuric acid is consumed

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Solution

The correct option is D sulphuric acid is consumed
Discharging the stored energy relies on both the positive and negative plates becoming lead(II) sulfate and the electrolyte losing much of its dissolved sulfuric acid. Hence, sulphuric acid is consumed.

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During discharging of lead-storage acid battery following reaction takes place:

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If 2.5 amp of current is drawn for 965 minutes, $H_{2} S O_{4}$ consumed is:

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