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Question

When a lift is going up with uniform acceleration, the apparent weight of a person is W1
When the lift is stationary, his apparent weight is W2
When the lift falls freely his apparent weight is W3
When the lift is going down with uniform acceleration which is less than the acceleration due to gravity, his apparent weight is W4
The increasing order of these four weights is

A
W1,W3,W2,W4
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B
W3,W4,W2,W1
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C
W3,W2,W4,W1
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D
W2,W3,W4,W1
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Solution

The correct option is C W3,W4,W2,W1
When lift accelerates up, pseudo force acts downwards, hence it increases apparent weight. W1>mg
When lift is stationary, W2=mg
When lift falls freely, it accelerates with g downwards, causing an upwards pseudo force in the frame of the lift equal to mg. Hence total force is 0. So weight is 0. W3=0
When lift accelerates down, pseudo force acts upwards, hence it decreases apparent weight W4<mg, but also the acceleration is less than g, therefore W4=m(ga)>0
Hence, W3<W4<W2<W1

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