When a metal plate is radiated with $1.6 \times 10^{16}$ Hz frequency, the kinetic energy of ejected electron is 3 times of kinetic energy when the same metal plate is irradiated with frequency of $10^{16}$ Hz. What is the threshold frequency of metal?

7 \times 10^{15} H z

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4.8 \times 10^{16} H z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.53 \times 10^{16} H z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 \times 10^{16} H z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $7 \times 10^{15} H z$
$K . E = h (v - v_{0})$
$K . E_{1} = h (10^{16} - v_{0})$ ........ (i)
$K . E_{2} = h (1.6 \times 10^{16} - v_{0})$ ........ (ii)
$K . E_{2} = 3 K . E_{1}$ ......... (iii)
From equation (i), (ii) and equation (iii)
$v_{0} = 7 \times 10^{15} H z$

Suggest Corrections

Similar questions

When a certain metal was irradiated with light of frequency $1.6 \times 10^{16} H z$ , the photoelectrons emitted had twice the kinetic energy as the photoelectrons emitted when the same metal was irradiated with light of frequency $1.0 \times 10^{16} H z$ . Calculate the threshold frequency ( $v_{0}$ ) for the metal.

Q. A certain metal was irradiated with light of frequency

3.2 \times 10^{16}

Hz. The photoelectrons emitted had twice the kinetic energy as did photoelectrons emitted when the same metal was irradiated with light of frequency

2 \times 10^{16}

Hz. Calculate the threshold frequency for the metal.

Q. A certain metal was initiated with light of frequency 3.2×10¹⁶Hz. The photoelectrons emitted had twice the kinetic energy as the same metal was irradiated with light of frequency 2×10¹⁶Hz.
Calculate the threshold frequency.

Q. When a certain metal was irradiated with light of frequency

3.2 \times 10^{16} H z

, the photoelectrons emitted has twice the kinetic energy as did photoelectrons emitted when the same metal was irradiated with light of frequency

2.0 \times 10^{16} H z

. Calculate

v_{0}

for the metal.

Q. A metal is irradiated with light of frequency

3.2 \times 10^{16} H z

. The ejected photoelectron has kinetic energy

\frac{3}{4}

th of the energy of the absorbed photon. The threshold frequency of the metal would be:

Join BYJU'S Learning Program

When a metal plate is radiated with 1.6×1016 Hz frequency, the kinetic energy of ejected electron is 3 times of kinetic energy when the same metal plate is irradiated with frequency of 1016 Hz. What is the threshold frequency of metal?

The correct option is A 7×1015 HzK.E=h(v−v0) K.E1=h(1016−v0) ........ (i) K.E2=h(1.6×1016−v0) ........ (ii) K.E2=3K.E1 ......... (iii) From equation (i), (ii) and equation (iii) v0=7×1015 Hz

When a metal plate is radiated with $1.6 \times 10^{16}$ Hz frequency, the kinetic energy of ejected electron is 3 times of kinetic energy when the same metal plate is irradiated with frequency of $10^{16}$ Hz. What is the threshold frequency of metal?

The correct option is A $7 \times 10^{15} H z$
$K . E = h (v - v_{0})$
$K . E_{1} = h (10^{16} - v_{0})$ ........ (i)
$K . E_{2} = h (1.6 \times 10^{16} - v_{0})$ ........ (ii)
$K . E_{2} = 3 K . E_{1}$ ......... (iii)
From equation (i), (ii) and equation (iii)
$v_{0} = 7 \times 10^{15} H z$