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Metals and Its Properties

When a mild-s...

Question

When a mild-steel specimen fails in a torsion test fracture looks like

A

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B

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C

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D

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Solution

The correct option is A
For brittle material of low tensile strength and much larger strength in compression and shear the twisting will cause fracture along spiral line at 45° to the axis of cylinder. For ductile material like mild steel, the plane of failure will be normal to the axis.

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Similar questions

Q. Consider the following statements:
P. Volume of specimen under uniaxial compression remain constant upto elastic limit.
Q. Brittle materials fails perpendicular to the axis of the bar under torsion.
R. Proportional limit, yield point and fracture point can be assumed same for mild steel specimen.
The correct option for above statements is:

Q. Assertion (A): A mild steel tension specimen subjected to an axial load fails along a surface at 45° to its axis.
Reason (R): Mild steel is weaker in shear than in tension and the place of maximum shear is at 45° to its axis

Q. Assertion (A): The failure surface of a mild steel torsion specimen subject to a torque about its axis is along a surface perpendicular to its axis.
Reason (R): Mild steel is relatively weaker in shear than in tension and the plane of maximum shear is perpendicular to its axis.

Q. In mild steel specimens subjected to tensile test cycle, the elastic limit in tension is raised and the elastic limit in compression is lowered. This is called

Q. Statement (I): The failure of a mild steel specimen of circular cross-section, subjected to a torque occurs along its cross-section.
Statement (II): The failure occurs on a plane of the specimen subjected to maximum shear stress; and mild steel is relatively weak in shear.

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