Question

# When a tension $$F$$ is applied, the elongation produced in uniform wire of length $$L$$, radius $$r$$ is $$e$$. When tension $$2F$$ is applied, the elongation produced in another uniform wire of length $$2L$$ and radius $$2r$$ made of same material is:

A
0.5e
B
1.0e
C
1.5e
D
2.0e

Solution

## The correct option is C $$1.0e$$$$Y = \dfrac{F / \pi r^{2}}{\triangle l/l}$$$$\triangle l = \dfrac{F l}{\pi r^{2} Y}$$$$E = \dfrac{F l}{\pi r^{2} Y} - ------1$$$$\triangle l = \dfrac{2 F 2l}{\pi 4 r^{2}Y}$$$$\triangle l = \dfrac{F l}{\pi r^{2}Y}= e$$   ---------- (By  1)=>  elongation  is  none  wire  is same as $$e$$Physics

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