When a train is stopped by applying break it stops after travelling a distance of 50 m. If speed of train is doubled and same retarding force is applied then it stops after travelling a distance of:
The correct option is C 200m
Let retardation is ‘a’.
Here train stops therefore final velocity , v=0
Using third equation of motion:
When speed of train is doubled, let train travel s2 distance
Using equation (i) we get