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Question

When an alkali metal is reacted with hydrogen then metallic hydride is formed. In this reaction:


A
hydrogen is oxidized
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B
hydrogen is reduced
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C
hydrogen is neither oxidised nor reduced
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D
hydrogen is oxidized as well as reduced
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Solution

The correct option is B hydrogen is reduced
Let M represents an alkali metal.
$$\displaystyle 2M+H_2 \to 2MH$$
$$\displaystyle MH$$ can be represented as $$\displaystyle M^++H^-$$
In this reaction, conversion of hydrogen an be represented as $$\displaystyle H_2 +2e^- \to 2H^-$$
Thus, a molecule of hydrogen accepts a pair of electrons to form 2 hydride ions. Gain of electrons is reduction. Hence, hydrogen is reduced to hydride ions.
Note: Alkali metal is oxidised to $$\displaystyle M^+$$ ions.

Chemistry

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