When an engine passes near to a stationary observer then its apparent frequencies occur in the ration $\frac{5}{3}$ . If the velocity of engine is

540 m / s

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270 m / s

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85 m / s

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52.5 m / s

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Solution

The correct option is C $85 m / s$
When engine approaches towards observer $n^{'} = n (\frac{v}{v - v_{s}})$
When engine going away from observer $n "= (\frac{v}{v + v_{s}}) n$
$∴ \frac{n^{'}}{n "} = \frac{v + v_{s}}{v - v_{s}} \Rightarrow \frac{5}{3} = \frac{340 + v_{s}}{340 - v_{s}} \Rightarrow v_{s} = 85$ m/s

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When an engine passes near to a stationary observer then its apparent frequencies occur in the ration 53. If the velocity of engine is

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