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Question

When an unpolarized light of intensity $${I}_{0}$$ is incident on a polarizing sheet, the intensity of the light which does not get transmitted is:


A
12I0
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B
14I0
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C
Zero
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D
I0
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Solution

The correct option is A $$\dfrac{1}{2} {I}_{0}$$
$$I={ I }_{ 0 }\cos ^{ 2 }{ \theta  } $$
Intensity of polarized light $$=\dfrac { { I }_{ 0 } }{ 2 } $$
$$\therefore$$ Intensity of untransmitted light $$={ I }_{ 0 }-\dfrac { { I }_{ 0 } }{ 2 } =\dfrac { { I }_{ 0 } }{ 2 } $$

Physics

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