When Ba(OH)₂ is added to NH₄Cl then which of the following reactions is correct regarding the products formed:

Ba(OH)₂ + 2NH₄Cl ---------> BaCl₂ + 2NH₃+ 2H₂O

OR

Ba(OH)₂+ 2NH₄Cl ----------> BaCl₂ + 2NH₄OH

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Solution

The reaction between barium hydroxide and ammonium chloride is an endothermic reaction. Heat is absorbed during endothermic reaction, fall in temperature is observed. SO NH3 and H20 not formed.

Ba(OH)2 +2NH4Cl → BaCl2 +2NH4OH

This reaction is called double displacement reaction.

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B a (O H)_{2} + 2 N H_{4} C l \to B a C l_{2} + 2 N H_{3} + X

Ba(OH)₂ + 2NH₄Cl ---------> BaCl₂ + 2NH₄OH

Is the above-mentioned chemical reaction correct?

When Ba(OH)₂ is mixed with NH₄Cl then why BaCl₂, NH₃ and H₂O is formed and not BaCl₂and NH₄OH?

In a given reaction, barium hydroxide reacts with ammonium chloride to form product X and Y. Identify X and Y.
Ba(OH)₂ + NH₄Cl → X + Y

The secondary reactions which takes place in dry cell are:

1) $M n O_{2} + N H_{4}^{+} + e^{-} \to M n O (O H) + N H_{3}$

2) $2 N H_{4} C l + 2 (O H^{-}) \to$ $2 N H_{3} + 2 C l^{-} + 2 H_{2} O$

3) $Z n + 2 M n O_{2} \to$ $[Z n (N H_{3})_{2}] + 2 O H^{-} + 2 M n O (O H)$

4) $Z n^{2 +} 2 N H_{3} + 2 C l^{-} \to$ $[Z n (N H_{3})_{2}] C l_{2} or Z n C l_{2} .2 N H_{3}$

Correct statements are:

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