When conc- NaCl is electrolysed using mercury as cathode and graphite as anode then which of the following is true -A- Pure Na is formed at cathodeB- Cl 2 is liberated at cathodeC- O 2 is liberated at cathodeD- Na -is reduced at cathode

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Nernst Equation

When conc. Na...

Question

When conc. NaCl is electrolysed using mercury as cathode and graphite as anode then which of the following is true :

C l_{2}

is liberated at cathode

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O_{2}

is liberated at cathode

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Pure Na is formed at cathode

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N a^{+}

is reduced at cathode

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Solution

The correct option is D $N a^{+}$ is reduced at cathode
At mercury cathode $N a^{+}$ are reduced instead of $H^{+}$ (Castner - Kellner cell)

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When conc. NaCl is electrolysed using mercury as cathode and graphite as anode then which of the following is true :

The correct option is D Na+ is reduced at cathodeAt mercury cathode Na+ are reduced instead of H+ (Castner - Kellner cell)

The correct option is D $N a^{+}$ is reduced at cathode
At mercury cathode $N a^{+}$ are reduced instead of $H^{+}$ (Castner - Kellner cell)