When divided by ( – 3) the polynomials 3 – 2 + + 6 & 23 – 2 – ( + 3) – 6 leave the same remainder. Find the value of ‘’.
p = 2
p = 1
p = 3
p = 4
p = 0
If the polynomials divided (2×3+ax*2+3x-5) and leave the same remainder when divided by (x-2 )find the value of "a"