When ethyl alcohol is passed over red hot copper at $300^{o} C$ , the formula of the product formed is

C H_{3} C H O

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C H_{3} C O C H_{3}

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C_{2} H_{4}

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C H_{3} C O O H

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Solution

The correct option is C $C H_{3} C H O$
When ethyl alcohol is passed over red hot copper at $300^{o} C$ , the product formed is acetaldehyde, $C H_{3} C H O$ .
The reaction is as follows:
$C_{2} H_{5} O H red hot Cu - ----- \to 300^{o} C C H_{3} C H O$

Suggest Corrections

Similar questions

C_{2} H_{5} O H

300^{o} C

573 K

C H_{3} C = C C H_{2} C H_{3} \frac{K M n O_{4} . K O H}{373 - 383 K}

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