When $F_{2}$ reacts with hot and concentrated alkali, then which of the following will be obtained?
(i) $O F_{2}$
(ii) $O_{2}$
(iii) $H_{2} O$
(iv) $N a F$

(i), (iii) and (iv)

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(ii) and (iii)

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(ii), (iii) and (iv)

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All of the above

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Solution

The correct option is C (ii), (iii) and (iv)
(i) Fluorine does not form oxyacids as it is most electronegative element of Periodic Table.
(ii) $2 F_{2} + N a O H H o t - --------- \to 4 N a F + O_{2} + 2 H_{2} O$
(iii) $F_{2} + 2 N a O H C o l d - --------- \to 2 N a F + O F_{2} + H_{2} O$
$∴ F_{2}$ reacts with hot $N a O H$ to give $N a F, O_{2}$ and $H_{2} O$ .

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When F2 reacts with hot and concentrated alkali, then which of the following will be obtained?(i) OF2(ii) O2(iii) H2O(iv) NaF

When $F_{2}$ reacts with hot and concentrated alkali, then which of the following will be obtained?
(i) $O F_{2}$
(ii) $O_{2}$
(iii) $H_{2} O$
(iv) $N a F$