When fluorine reacts with hot and conc. NaOH then products obtained are:

N a F + H_{2} O + O_{2}

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N a F + H_{2} O + O F_{2}

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H F + N a F + H_{2} O

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N a F + H F + O_{2}

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Solution

The correct option is A $N a F + H_{2} O + O_{2}$
$F_{2} + 2 N a O H \to 2 N a F + H_{2} O + \frac{1}{2} O_{2}$
hot-conc
$N a F, H_{2} O a n d O_{2} a r e f o r m e d$

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