When $K M n O_{4}$ acts as an oxidizing agent and ultimately forms $M n O_{4}^{- 2}$ , $M n O_{2}$ , $M n_{2} O_{3}$ and $M n^{+ 2}$ , then the number of electrons transferred ( per Mn atom) in each case respectively is:

4, 3, 1, 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1, 5, 3, 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1, 3, 4, 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3, 5, 7, 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
1, 3, 4, 5

Check the oxidation states of Mn.
$⟹$ No of electrons transferred will be change in oxidation state

$+ 7 M n O_{4}^{-} + e^{-} ⟶ + 6 M n O_{4}^{- 2}$

$+ 7 M n O_{4}^{-} + 3 e^{-} ⟶ + 4 M n O_{2}$

$+ 7 M n O_{4}^{-} + 4 e^{-} ⟶ + 3 M n_{2} O_{3}$ ;

$+ 7 M n O_{4}^{-} + 5 e^{-} ⟶ + 2 M n^{2 +}$

Suggest Corrections

Similar questions

When $K M n O_{4}$ acts as an oxidizing agent and ultimately forms $M n O_{4}^{- 2}$ , $M n O_{2}$ , $M n_{2} O_{3}$ and $M n^{+ 2}$ , then the number of electrons transferred ( per Mn atom) in each case respectively is:

Q. When

K M n O_{4}

acts as an oxidizing agent & ultimately forms

[M n O_{4}]^{2 -}, M n O_{2}, M n_{2} O_{3}, M n^{+ 2},

then the number of electrons transferred in each case respectively is

K M n O_{4}

acts as an oxidising agent and ultimately forms

[M n O_{4}^{2 -}, M n O_{2}, M n_{2} O_{3}]

and

M n^{+ 2} .

Then the number of electrons transferred in each case respectively is:

Q. When

K M n O_{4}

acts as an oxidising agent and ultimately forms

M n O_{4}^{2 -}

M n O_{2}

M n_{2} O_{3}

and

M n^{2 +}

, then the number of electrons transferred per molecule of

K M n O_{4}

in each case respectively, is:

Join BYJU'S Learning Program

When KMnO4 acts as an oxidizing agent and ultimately formsMnO−24 ,MnO2 ,Mn2O3 andMn+2 , then the number of electrons transferred ( per Mn atom) in each case respectively is:

The correct option is C 1, 3, 4, 5 Check the oxidation states of Mn. ⟹ No of electrons transferred will be change in oxidation state +7MnO−4+e−⟶+6MnO−24 +7MnO−4+3e−⟶+4MnO2 +7MnO−4+4e−⟶+3Mn2O3; +7MnO−4+5e−⟶+2Mn2+

When $K M n O_{4}$ acts as an oxidizing agent and ultimately forms $M n O_{4}^{- 2}$ , $M n O_{2}$ , $M n_{2} O_{3}$ and $M n^{+ 2}$ , then the number of electrons transferred ( per Mn atom) in each case respectively is: