Question

When lead nitrate reacts with potassium iodide, yellow precipitate of

• A. $Pb{I}_2$ is formed
• B. $KN{O}_3$ is formed
• C. $Pb(N{O}_3{)}_2$ is formed
• D. $PbI{O}_3$ is formed

Answer 1

The correct option is A

$Pb{I}_2$ is formed

$Pb\left(N{O}_3{)}_2\right(aq)+2KI(aq)\to Pb{I}_2(\downarrow )+2KN{O}_3(aq)$
$Pb{I}_2$ is yellow precipitate.