When mercuric iodide is added to the aqueous solution of potassium iodide,

Freezing point is raised

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Freezing point is lowered

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Freezing point does not change

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Boiling point does not change

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Solution

The correct option is A Freezing point is raised
During complex formation, more number of particles join to form a larger particle which does not break. So the particle number is reduced an the freezing point is elevated.
$2 K I + H g l_{2} ⇌ K_{2} H g I_{4} K_{2} [H g I_{4}] ⇌ 2 K^{\oplus} + H g I_{4}^{2 -}$

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When mercuric iodide is added to the aqueous solution of potassium iodide,

K I

H g I_{2}

K I

[H g I_{4}]^{2 -}

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