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Question

When NaCl is doped with 105 moles % of SrCl2, what is the number of cationic vacancies per mole? 


A
105×NA
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B
107×NA
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C
2×107NA
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D
None of these
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Solution

The correct option is B 107×NA

Given,

NaCl is doped with 10-5 moles % of SrCl2.This means, 100 moles of NaCl are doped with 10-5 moles of SrCl2.

Therefore, 1mole of NaCl is doped with 10-5 /100 = 10-7 moles of SrCl2 or 10-7 moles of Sr2+.

Now,

One Sr2+ ion create one cation vacancy.

Therefore, no. of cation vacancies created by 10-7 moles Sr2+

= 10-7 moles/mole of NaCl

= 10-7 x 6.022 x 1023 / mole of NaCl = 107×NA


Chemistry

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