Question

When nitrobenzene is treated with ${Br}_2$, in the presence of ${FeBr}_3$, the major product formed is m-bromonitrobenzene. Statements which are related to obtaining the m-isomer are :

• A. electron density on meta-carbon is more than that on ortho- and para-positions
• B. intermediate carbonium ion formed after initial attack of ${Br}^{\oplus }$ at the meta-position is least destabilised
• C. loss of aromaticity when ${Br}^{\oplus }$ attacks at the ortho- and para-positions and not at meta-position
• D. easier loss of $H^{\oplus }$ to regain aromaticity from the meta position than from the ortho- and para-positions

Answer 1

Answer: (A), (D)

The correct options are
A electron density on meta-carbon is more than that on ortho- and para-positions
D easier loss of $H^{\oplus }$ to regain aromaticity from the meta position than from the ortho- and para-positions

nitro group is an electron withdrawing groups so it withdraws electron density more from ortho and para partious than meta position .when $B{r}_2$ in presence of $FeB{r}_3$ reacts ,it is are electrophilic reaction .so,meta position slightly reacts faster and also the H+ of meta is more audic than ortho and para position