When propionic acid is treated with aqueous $N a H C O_{3}, C O_{2}$ is liberated.The 'C' of $C O_{2}$ comes from:

methyl group

No worries! We‘ve got your back. Try BYJU‘S free classes today!

carboxylic acid group

No worries! We‘ve got your back. Try BYJU‘S free classes today!

methylene group

No worries! We‘ve got your back. Try BYJU‘S free classes today!

bicarbonate

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D bicarbonate
When propionic acid is treated with aqueous sodium bicarbonate, $C O_{2}$ is liberated. The $C$ from $C O_{2}$ comes from bicarbonate.
$C H_{3} C H_{2} C O O H + N a H C O_{3} \to C H_{3} C H_{2} C O O N a + H 2 O + C O_{2} ↑$
Option (D) is correct.

Suggest Corrections

Similar questions

C O_{2}

C O_{2}

C O_{2}

C O_{2}

When propionic acid is treated with aqueous sodium bicarbonate, $C O_{2}$ is liberated. The C of $C O_{2}$ comes from:

N a H C O_{3}, C O_{2}

C O_{2}

N a H C O_{3},

Join BYJU'S Learning Program