Question

When same amount of zinc is treated separately with excess of 1$H_{2}S{O}_4$ and $NaOH$, the ratio of volumes of $H_2$ evolved is:

• A. 1 : 1
• B. 1 : 2
• C. 2 : 1
• D. 9 : 4

Answer 1

The correct option is A 1 : 1

$Zn+H_{2}S{O}_4\to ZaS{O}_4+H_2$

$Zn+2NaOH\to N{a}_{2}Zn{O}_2+H_2$

Hence when same amount of zinc is treated separately with excess of sulphuric acid and $NaOH$, the ratio of volumes of $H_2$ evolve is $1:1$.