When the current in a coil changes from 8 ampere to 2 ampere in 3 - 10-2 second- the e-m-f- induced in the coil is 2 volt- The self inductance of the coil in millinery is

The correct option is A 1 E.M.F. = L didt 2 = L ×8 23 × 10^ 2 L = 1 millineryHere (A) is correct answer ...

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Standard XII

Physics

Mutual Induction

When the curr...

Question

When the current in a coil changes from 8 ampere to 2 ampere in $3 \times 10^{- 2}$ second, the e.m.f. induced in the coil is 2 volt. The self inductance of the coil (in millinery) is

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Solution

The correct option is A 1
$E . M . F . = L \frac{d i}{d t}$

$2 = L \times \frac{8 - 2}{3 \times 10^{- 2}}$

L = 1 millinery

Here (A) is correct answer

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When the current in a coil changes from 8 ampere to 2 ampere in 3×10−2 second, the e.m.f. induced in the coil is 2 volt. The self inductance of the coil (in millinery) is

The correct option is A 1E.M.F.=Ldidt2=L×8−23×10−2L = 1 millineryHere (A) is correct answer

When the current in a coil changes from 8 ampere to 2 ampere in $3 \times 10^{- 2}$ second, the e.m.f. induced in the coil is 2 volt. The self inductance of the coil (in millinery) is

The correct option is A 1
$E . M . F . = L \frac{d i}{d t}$

$2 = L \times \frac{8 - 2}{3 \times 10^{- 2}}$

L = 1 millinery

Here (A) is correct answer