When the displacement is half of the amplitude, the ratio of potential energy to the total energy is
A
12
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B
14
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C
1
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D
18
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Solution
The correct option is B14 Potential energy is given by UP=12mω2y2 where, y is the displacement of particle from its mean position. Here y=A2, ∴UP=12mω2A24 Total energy is given by E=12mω2A2 ⇒UPE=14.