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Question
When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased fro m emitted 0.5 eV to 0.8 eV. The work function of the metal is :
When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased fro m emitted 0.5 eV to 0.8 eV. The work function of the metal is :
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Solution
The correct option is C 1.0 eV
From photoelectric equation, KEmax=hv−Ψ
0.5eV=hv−Ψ .... (1)
0.8eV=1.2hv−Ψ .... (2)
on solving we get, Ψ=1eV
From photoelectric equation, KEmax=hv−Ψ
0.5eV=hv−Ψ .... (1)
0.8eV=1.2hv−Ψ .... (2)
on solving we get, Ψ=1eV
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