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Question

When the load on a wire is slowly increased from 3 to 5 kgwt, the elongation increases from 0.61 mm to 1.02 mm. The work done during the extension of wire is


A
0.16 J
loader
B
0.016 J
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C
1.6 J
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D
16 J
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Solution

The correct option is B 0.016 J
Work done = F×Δl2
Wi=3×9.81×0.61×1032
Wf=5×9.81×1.02×1032
ΔW=WfWi=0.016 J

Physics

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