Question

When two dice are rolled:

(i) List the outcomes for the event that the total is odd.

(ii) Find probability of getting an odd total.

(iii) List the outcomes for the event that total is less than 5.

(iv) Find the probability of getting a total less than 5?

Answer 1

$\because$ Every dice has 6 number from 1 to 6.

$\therefore$ Total outcomes $=6\times 6=36.$

(i) List of outcomes for event then the total is odd will be (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3,2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5)

(ii) Probability of getting an odd total

Let A be the favourable outcomes which are 18

Then $P\left(A\right)=\frac{18}{36}=\frac{1}{2}$

(iii) List of outcomes for the event that total is less than 5 are (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 1), which are 6.

(iv) Probability of getting a total less than 5 Let B be the favourable outcome,

Then $P\left(B\right)=\frac{6}{36}=\frac{1}{6}$