When two dice are thrown simultaneously, the probability of getting the same even number on both the dice is

\frac{1}{2}

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\frac{5}{12}

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\frac{1}{12}

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\frac{11}{12}

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Solution

The correct option is D $\frac{1}{12}$
Total points in samples space $= 36$
Favorable cases $= 3 = (2, 2) (4, 4) (6, 6)$
$\Rightarrow P = 3 / 36 = 1 / 12$

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When two dice are thrown simultaneously, the probability of getting the same even number on both the dice is

The correct option is D 112Total points in samples space=36Favorable cases =3=(2,2)(4,4)(6,6)⇒P=3/36=1/12

The correct option is D $\frac{1}{12}$
Total points in samples space $= 36$
Favorable cases $= 3 = (2, 2) (4, 4) (6, 6)$
$\Rightarrow P = 3 / 36 = 1 / 12$