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Question

Which among the following is a factor of x2+x6−16?

A
3x+1
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B
2x+1
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C
x15
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D
x12
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Solution

The correct option is B 2x+1
x2+x616

=6x2+x16

=16(6x2+x1)

Now, we will factorise the polynomial by splitting its middle term.

16(6x2+x1)

=16(6x2+3x2x1)

=16(3x(2x+1)1(2x+1))

=16(3x1)(2x+1)

Therefore, 16,(3x1) and (2x+1) are factors of x2+x616.

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